Answer
$ \frac{9}{(9-x^2)^{3/2}}$
Work Step by Step
$\frac{(9-x^2)^{1/2}+x^2(9-x^2)^{-1/2}}{9-x^2}=\frac{(9-x^2)+x^2}{(9-x^2)^{3/2}}=\frac{9}{(9-x^2)^{3/2}}$
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