Answer
$ \frac{-2\sqrt[3]3}{3} $
Work Step by Step
$\frac{-2}{\sqrt[3] 9}=\frac{-2}{\sqrt[3] 9}\times\frac{\sqrt[3]3}{\sqrt[3]3}=\frac{-2\sqrt[3]3}{3} $
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A61: 52
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