Answer
$-2$
Work Step by Step
For any odd counting number $n$, $\sqrt[n]{a^n}=a$.
Thus,
$
\sqrt[3]{-8}=\sqrt[3]{(-2)^3}=-2
.$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 9
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