Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 8

Answer

$2$

Work Step by Step

For $a\gt0$, $\sqrt[n]{a^n}=a$. Thus, $ \sqrt[4]{16}=\sqrt[4]{2^4}=2$
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