Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 12

Answer

$3\sqrt[3] 2$

Work Step by Step

For positive real numbers $a$ and $b$, $\sqrt[n]{a}\cdot \sqrt[n]{b}=\sqrt[n]{ab}$. Thus, $ \sqrt[3]{54}=\sqrt[3]{27(2)}=\sqrt[3]{27} \cdot \sqrt[3]2=3\cdot \sqrt[3] 2=3\sqrt[3]2 $
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