Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 33

Answer

$-\sqrt[3]{2 }$

Work Step by Step

We simplify by using the fact that $\sqrt[n]{a}=a^{1/n}$ and then combine the like terms as follows: $$ 5\sqrt[3] 2-2\sqrt[3]{54}=5\sqrt[3] 2-2\sqrt[3]{2\times3^3} =5\sqrt[3] 2-6\sqrt[3]{2 }\\=(5-6)\sqrt[3]{2 } =-\sqrt[3]{2 } .$$
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