Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 30

Answer

$-5\sqrt 3$

Work Step by Step

We have $$ 2\sqrt{12}-3\sqrt{27}= 2\sqrt{3\times2^2}-3\sqrt{3\times3^2}\\ =4\sqrt 3-9\sqrt 3 .$$ Now, we simplify by factoring out $\sqrt 3$ and then combine the like terms as follows: $$ 4\sqrt 3-9\sqrt 3=(4-9)\sqrt 3=-5\sqrt 3 .$$
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