Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 23

Answer

$ 15\sqrt[3] 3$

Work Step by Step

$(\sqrt 5\sqrt[3] 9)^2=5\sqrt[3] {3^4}=15\sqrt[3] 3$
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