Answer
$12\sqrt3$
Work Step by Step
We apply the rule:
$\sqrt{a}\sqrt{b}=\sqrt{ab}$
Thus, we have:
$$
(3\sqrt{6})(2\sqrt{2})=6\sqrt{6\times2}=6\sqrt{3\times2\times2}\\
=6\sqrt{3\times2^2}=12\sqrt3
.$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 25
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