Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 15

Answer

$x^3y^2$

Work Step by Step

Use the rule $\sqrt[n]{a^n}=n, a\gt0$ to obtain $$ \sqrt[4]{x^{12}y^8}=\sqrt[4]{(x^3y^2)^4}=x^3y^2 $$
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