Answer
$ \sqrt[3] {2x}(2x-1)$
Work Step by Step
$\sqrt[3] {16x^4}-\sqrt[3] {2x}=\sqrt[3] {2^4x^4}-\sqrt[3] {2x}=2x\sqrt[3] {2x}-\sqrt[3] {2x}=\sqrt[3] {2x}(2x-1)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 37
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