Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.3 - Double-Angle, Power-Reducing, and Half-Angle Formulas - Exercise Set - Page 680: 6

Answer

The exact value of the trigonometric function $\tan 2\alpha $ is $\frac{336}{527}$

Work Step by Step

Calculate the value of $\tan 2\alpha $. Recall the double angle formula. $\begin{align} & \tan 2\alpha =\frac{2\tan \alpha }{1-{{\tan }^{2}}\alpha } \\ & =\frac{2\left( \frac{\text{perpendicular}}{\text{base}} \right)}{1-{{\left( \frac{\text{perpendicular}}{\text{base}} \right)}^{2}}} \end{align}$ Substitute $24$ for the base and $7$ for the perpendicular. $\begin{align} & \tan 2\alpha =\frac{2\left( \frac{\text{7}}{\text{24}} \right)}{1-{{\left( \frac{\text{7}}{\text{24}} \right)}^{2}}} \\ & =\frac{\left( \frac{\text{7}}{\text{12}} \right)}{1-\frac{49}{576}} \\ & =\frac{\left( \frac{\text{7}}{\text{12}} \right)}{\frac{527}{576}} \\ & =\frac{336}{527} \end{align}$ Therefore, the exact value of the trigonometric function $\tan 2\alpha $ is $\frac{336}{527}$.
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