Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1059: 1

Answer

$200,220,240,260,280,300$

Work Step by Step

Formula to calculate the nth term of an arithmetic sequence is: $a_n=a_1+d(n-1)$ Here, $a_1: $ First term and $d=$ common difference $a_1=200+20(1-1)=200$; $a_2=200+20(2-41)=220$;$a_3=200+20(3-1)=240$;$a_4=200+20(2-1)=260$; $a_5=200+20(5-1)=280$;$a_6=200+20(6-1)=300$ Hence, the first six terms are: $200,220,240,260,280,300$
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