Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1059: 10

Answer

$-7,-3,1,5,9,13$

Work Step by Step

Formula to calculate the nth term of an arithmetic sequence is: $a_n=a_1+d(n-1)$ Here, $a_1: $ First term and $d=$ common difference Since, we have $a_1=-7$ Use a recursion formula to find the remaining five terms. Then $a_2=a_1+4=-7+4=-3;\\a_3=a_2+4=-3+4=1;\\a_4=a_3+4=1+4=5;\\a_5=a_4+4=5+4=9;\\a_6=a_5+4=9+4=13$ Hence, the first six terms are: $-7,-3,1,5,9,13$
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