Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1059: 14

Answer

$-1.7,-2.0,-2.3,-2.6,-2.9,-3.2$

Work Step by Step

Formula to calculate the nth term of an arithmetic sequence is: $a_n=a_1+d(n-1)$ Here, $a_1: $ First term and $d=$ common difference Since, we have $a_1=-1.7$ Use a recursion formula to find the remaining five terms. Then $a_2=a_1-0.3=-1.7-0.3=-2.0;\\a_3=a_2-0.3=-2.0-0.3=-2.3;\\a_4=a_3-0.3=-2.3-0.3=-2.6;\\a_5=a_4-0.3=-2.6-0.3=-2.9;\\a_6=a_5-0.3=-2.9-0.3=-3.2$ Hence, the first six terms are: $-1.7,-2.0,-2.3,-2.6,-2.9,-3.2$
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