Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1059: 2

Answer

$300,350,400,450,500,550$

Work Step by Step

Formula to calculate the nth term of an arithmetic sequence is: $a_n=a_1+d(n-1)$ Here, $a_1: $ First term and $d=$ common difference $a_1=300+50(1-1)=300$; $a_2=300+50(2-1)=350$;$a_3=300+50(3-1)=400$;$a_4=300+50(4-1)=450$; $a_5=300+50(5-1)=500$;$a_6=300+50(6-1)=550$ Hence, the first six terms are: $300,350,400,450,500,550$
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