Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1059: 4

Answer

$-8,-3,2,7,12,17$

Work Step by Step

Formula to calculate the nth term of an arithmetic sequence is: $a_n=a_1+d(n-1)$ Here, $a_1: $ First term and $d=$ common difference $a_1=-8+5(1-1)=-8$; $a_2=-8+5(2-1)=-3$;$a_3=-8+5(3-1)=2$;$a_4=-8+5(4-1)=7$; $a_5=-8+5(5-1)=12$;$a_6=-8+5(6-1)=17$ Hence, the first six terms are: $-8,-3,2,7,12,17$
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