Answer
$sin(\theta) =\frac{4}{5}$,
$cos(\theta) =-\frac{3}{5}$,
$tan(\theta) =-\frac{4}{3}$,
$cot(\theta) =-\frac{3}{4}$,
$sec(\theta) =-\frac{5}{3}$,
$csc(\theta) =\frac{5}{4}$.
Work Step by Step
Given $x=-3,y=4$, the terminal side is in quadrant II with $r=\sqrt {x^2+y^2}=5$, we have:
$sin(\theta)=\frac{y}{r}=\frac{4}{5}$,
$cos(\theta)=\frac{x}{r}=-\frac{3}{5}$,
$tan(\theta)=\frac{y}{x}=-\frac{4}{3}$,
$cot(\theta)=\frac{x}{y}=-\frac{3}{4}$,
$sec(\theta)=\frac{r}{x}=-\frac{5}{3}$,
$csc(\theta)=\frac{r}{y}=\frac{5}{4}$.
