Answer
$-\frac{\sqrt3}{2}.$
Work Step by Step
$f(-\theta)=sin (-60^{O})=sin\frac{-\pi}{3}=-\frac{\sqrt3}{2}.$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 105
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