Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 37

Answer

$\sqrt6$.

Work Step by Step

$\csc{45^\circ}\cdot\tan{60^\circ}=\csc{\frac{\pi}{4}}\cdot\tan{\frac{\pi}{3}}=\sqrt2\cdot\sqrt3=\sqrt6$.
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