Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 32

Answer

$\frac{1}{2}-\frac{\sqrt2}{2}$.

Work Step by Step

$\sin{30^\circ}-\cos{45^\circ}=\sin{\frac{\pi}{6}}-\cos{\frac{\pi}{4}}=\frac{1}{2}-\frac{\sqrt2}{2}$.
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