Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 35

Answer

$\dfrac {1}{2}$

Work Step by Step

$\sin 45^o\cos 45^o=\sin \dfrac {\pi }{4}\times \cos \dfrac {\pi }{4}=\dfrac {\sqrt {2}}{2}\times \dfrac {\sqrt {2}}{2}=\dfrac {2}{4}=\dfrac {1}{2}$
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