Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 47

Answer

$sin(t) =\frac{\sqrt 3}{2}$, $cos(t) =-\frac{1}{2}$, $tan(t) =-\sqrt 3$, $cot(t) =-\frac{\sqrt 3}{3}$, $sec(t) =-2$, $csc(t) =\frac{2\sqrt 3}{3}$.

Work Step by Step

Given $t=\frac{2\pi}{3}$, the terminal side is in quadrant II and $\frac{\pi}{3}$ to the $-x$-axis , we have: $sin(t)=y=\frac{\sqrt 3}{2}$, $cos(t)=x=-\frac{1}{2}$, $tan(t)=\frac{y}{x}=-\sqrt 3$, $cot(t)=\frac{x}{y}=-\frac{\sqrt 3}{3}$, $sec(t)=\frac{1}{x}=-2$, $csc(t)=\frac{1}{y}=\frac{2\sqrt 3}{3}$.
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