Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 43

Answer

$2\sqrt2+\frac{4\sqrt3}{3}$.

Work Step by Step

$2\sec{\frac{\pi}{4}}+4\cot{\frac{\pi}{3}}=2(\sqrt2)+4\frac{\sqrt3}{3}=2\sqrt2+\frac{4\sqrt3}{3}$.
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