Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 38

Answer

$\frac{2\sqrt3}{3}$.

Work Step by Step

$\sec{30^\circ}\cdot\cot{45^\circ}=\sec{\frac{\pi}{6}}\cdot\cot{\frac{\pi}{4}}=\frac{2}{\sqrt3}\cdot1=\frac{2\sqrt3}{3}$.
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