Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 140

Answer

$2(4x+5)^2(5x+1)(50x+31)$

Work Step by Step

The given expression is $3(4x+5)^2\cdot 4(5x+1)^2+(4x+5)^3\cdot 2(5x+1)\cdot 5$ $=12(4x+5)^2(5x+1)^2+10(4x+5)^3(5x+1)$ Factor out $2(4x+5)^2(5x+1)$. $=2(4x+5)^2(5x+1)[6(5x+1)+5(4x+5)]$ Use distributive property. $=2(4x+5)^2(5x+1)[30x+6+20x+25]$ Add like terms. $=2(4x+5)^2(5x+1)(50x+31)$ Hence, the completely factored form of the given expression is $2(4x+5)^2(5x+1)(50x+31)$.
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