Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 136

Answer

$6(x+5)^3(x-1)(x+1)$

Work Step by Step

The given expression is $4(x+5)^3(x-1)^2+(x+5)^4\cdot 2(x-1)$. Factor out $2(x+5)^3(x-1)$. $=2(x+5)^3(x-1)[2(x-1)+(x+5)]$ Use distributive property. $=2(x+5)^3(x-1)[2x-2+x+5]$ Add like terms. $=2(x+5)^3(x-1)[3x+3]$ Factor out $3$. $=2(x+5)^3(x-1)(3)(x+1)$ $=6(x+5)^3(x-1)(x+1)$ Hence, the completely factored form of the given expression is $6(x+5)^3(x-1)(x+1)$.
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