Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 127

Answer

The number to add is $9$. The factored form is $(y-3)^2$.

Work Step by Step

The given expression is $y^2-6y$. This is in the form of $y^2-by$ where $b=6$. To find the number needed to complete the square, use the formula $\left(\frac{1}{2}b\right)^2$. $\Rightarrow \left(\frac{1}{2}b\right)^2=\left(\frac{1}{2}\cdot 6\right)^2=3^2=9$ Add $9$ to the given expression. $=y^2-6y+9$ $=y^2-2\cdot 3 \cdot y+3^2$ Use the special formula $a^2-2ab+b^2=(a-b)^2$ where $a=y$ and $b=3$. $=(y-3)^2$ Hence, the factored form is $(y-3)^2$.
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