Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 131

Answer

$2(3x+4)(9x+13)$

Work Step by Step

The given expression is $2(3x+4)^2+(2x+3)\cdot 2(3x+4)\cdot 3$. Factor out $2(3x+4)$. $=2(3x+4)[(3x+4)+3(2x+3)]$ Use distributive property. $=2(3x+4)(3x+4+6x+9)$ Add like terms. $=2(3x+4)(9x+13)$. Hence, the factored form is $2(3x+4)(9x+13)$.
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