Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 134

Answer

$x^2(32x-9)$

Work Step by Step

The given expression is $3x^2(8x-3)+x^3\cdot 8$. Factor out $x^2$. $=x^2[3(8x-3)+8x]$ Use distributive property. $=x^2[24x-9+8x]$ Add like terms. $=x^2(32x-9)$ Hence, the completely factored form is $x^2(32x-9)$.
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