Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 126

Answer

The number to add is $49$. The factored form is $(p+7)^2$.

Work Step by Step

The given expression is $p^2+14p$. This is in the form of $p^2+bp$ where $b=14$. To find what number must be added to compelte the square, use the formula $\left(\frac{1}{2}b\right)^2$. $\Rightarrow \left(\frac{1}{2}b\right)^2=\left(\frac{1}{2}\cdot 14\right)^2=7^2=49$ Add $49$ to the given expression. $=p^2+14p+49$ $=p^2+2\cdot 7 \cdot p+7^2$ Use the special formula $a^2+2ab+b^2=(a+b)^2$ where $a=p$ and $b=7$. $=(p+7)^2$ Hence, the factored form is $(p+7)^2$.
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