Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 132

Answer

$(2x+1)(30x-19)$

Work Step by Step

The given expression is $5(2x+1)^2+(5x-6)\cdot 2(2x+1)\cdot 2$ $=5(2x+1)^2+4(5x-6)(2x+1)$ Factor out $(2x+1)$. $=(2x+1)[5(2x+1)+4(5x-6)]$ Use distributive property. $=(2x+1)[10x+5+20x-24]$ Add like terms. $=(2x+1)(30x-19)$. Hence, the completely factored form is $(2x+1)(30x-19)$.
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