Answer
$3(4x-3)(4x-1)$
Work Step by Step
The given expression is
$(4x-3)^2+x\cdot 2(4x-3)\cdot 4$
$=(4x-3)^2+8x(4x-3)$
Factor out $(4x-3)$.
$=(4x-3)[(4x-3)+8x]$
$=(4x-3)[4x-3+8x]$
Add like terms.
$=(4x-3)(12x-3)$
Factor out $3$.
$=(4x-3)(3)(4x-1)$
$=3(4x-3)(4x-1)$
Hence, the completely factored form of the given expression is $3(4x-3)(4x-1)$.
