Answer
$\int^{1}_{0}sin x^2dx\leq=\int^{1}_{0}sinx^2dx $ cannot equal 2
Work Step by Step
-1$\leq sin(x^2)\leq 1 $ for all x=(1-0)(-1) $\leq\int^{1}_{0} sin(x^2)dx\leq(1-0)(1)$
or
$\int^{1}_{0}sin x^2dx\leq=\int^{1}_{0}sinx^2dx $ cannot equal 2
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 276: 75
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