Answer
0
Work Step by Step
$av(f)=(\frac{1}{\sqrt{3}-0})\int^{\sqrt{3}}_{0}(x^2-1)dx$
=$\frac{1}{\sqrt{3}}\int^{\sqrt{}3}_{0}x^2dx-\frac{1}{\sqrt{3}}\int^{\sqrt{3}}_{0}1dx$
=$\frac{1}{\sqrt{3}}(\frac{(\sqrt{3}^3)}{3})-\frac{1}{\sqrt{3}}(\sqrt{3}-0)=1-1=0$
