Answer
-$\frac{3}{2}$
Work Step by Step
av(f)=$(\frac{1}{3-0})\int^{3}_{0}(-\frac{x^2}{2})dx$
$=\frac{1}{3}(-\frac{1}{2})\int^{3}_{0}x^2dx$
=$\frac{1}{6}(\frac{3^3}{3})$
=-$\frac{3}{2}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 276: 56
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