Answer
-2
Work Step by Step
av(f)=$(\frac{1}{1-0})\int^{1}_{0}(-3x^2-1)dx$
=3$\int_{0}^{1}x^2dx-\int^{1}_{0}3dx$
=$(\frac{1^3}{3})-3(1-0)=-2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 276: 58
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
