Answer
7
Work Step by Step
$\int^{1}_{\frac{1}{2}}24u^2du$
=24$\int^{1}_{\frac{1}{2}}u^2du$
=$24[\int_{0}^{1}u^2du-\int^{\frac{1}{2}}_{0}u^2du$
=$24[\frac{1^3}{3}-\frac{(\frac{1}{2})^3}{3}]$
=24$[\frac{\frac{7}{8}}{3}]$
=7
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 275: 48
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