Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 275: 32

Answer

24

Work Step by Step

$\int_{\sqrt{2}}^{5\sqrt{2}} r dr$ =$\frac{(5\sqrt{2})^2}{2}-\frac{(\sqrt{2})^2}{2}$ =24
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