Answer
-1
Work Step by Step
$\int^{\sqrt{2}}_{0}(t-\sqrt{2})$
=$\int^{\sqrt{2}}_{0}tdt -\int^{\sqrt{2}}_{0}\sqrt{2} dt$
=$[\frac{(\sqrt{2})^2}{2}-\frac{0^2}{2}]-\sqrt{2}[\sqrt{2}-0]$
=1-2
=-1
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 275: 44
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