Answer
=$\frac{3\pi^2}{2}$
Work Step by Step
$\int^{2\pi}_\pi\theta \ d\theta$=$\frac{(\sqrt 2\pi)^2}{2}-\frac{\pi^2}{2}$
=$\frac{3\pi^2}{2}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 275: 31
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