Answer
0
Work Step by Step
$\int^{0}_{3}(2z-3)dz$
=$\int^{0}_{3}2zdz-\int^{0}_{3}3 dz$
=-2$\int^{3}_{0}zdz-\int^{0}_{3}3dz$
=-2$[\frac{3^2}{2}-\frac{0^2}{2}]$
=-3[0-3]
=-9+9
=0
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 275: 46
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