Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 275: 26

Answer

$\frac{3}{2}(b^2 - a^2)$

Work Step by Step

$\int_a^b 3tdt$ =$\frac{1}{2}b(3b)-\frac{1}{2}a(3a)$ =$\frac{3}{2}(b^2 - a^2)$
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