Answer
=$\frac{-7}{4}$
Work Step by Step
$\int^1_2(1+\frac{z}{2}) \ dz$=$\int^1_21 \ dz+\int^1_2\frac{z}{2} \ dz$
=$\int^1_2 1 \ dz-\frac{1}{2}\int^2_1 z \ dz$
=$1[1-2]-\frac{1}{2}[\frac{2^2}{2}-\frac{1^2}{2}]$
=$-1-\frac{1}{2}(\frac{3}{2})$=$-\frac{7}{4}$
