Answer
a)-$\sqrt{2}$
b)$\sqrt{2}$
c)-$\sqrt{2}$
d)1
Work Step by Step
a)$\int_0^{-3} g(t) dt$=-$\int_0^{3} g(t) dt$=-$\sqrt{2}$
b)$\int^0_{-3} g(t) dt$=$\int^0_{-3} g(t) dt$=$\sqrt{2}$
c)$\int^0_{-3} g(t) dt$[-g(x)]dx=-$\int^0_{-3} g(x) dx$=-$\sqrt{2}$
d)$\int^0_{-3} \frac{g(t)}{\sqrt{2}} dr$=$\frac{1}{\sqrt{2}}$$\int^0_{-3} g(t) dt$=($\frac{1}{\sqrt{2}})(\sqrt{2})=1$
