Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 275: 40

Answer

$9b^3$

Work Step by Step

$\int_{0}^{\sqrt{3b}}x^2dx$ =$\frac{(a\sqrt{3})^3}{2}$ =$9b^3$
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