Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 180: 98

Answer

$1$

Work Step by Step

$\lim_{\theta\to0}\frac{sin(sin\theta)}{\theta}=\lim_{\theta\to0}\frac{sin(sin\theta)}{sin\theta}\frac{sin\theta}{\theta}=\lim_{sin\theta\to0}\frac{sin(sin\theta)}{sin\theta}\lim_{\theta\to0}\frac{sin\theta}{\theta}=(1)(1)=1$
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