Answer
$-2$
Work Step by Step
$\lim_{x\to0}\frac{3x-tan7x}{2x}=\lim_{x\to0}(\frac{3}{2}-\frac{sin7x}{2x\cdot cos7x})=\frac{3}{2}-\lim_{x\to0}(\frac{sin7x}{7x}\frac{7}{2cos7x})=\frac{3}{2}-\frac{7}{2}=-2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Practice Exercises - Page 180: 96
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