Answer
$-40m^2/s$
Work Step by Step
Given $\frac{dr}{dt}=-\frac{2}{\pi}$ m/sec, at $r=10m$, with $A=\pi r^2$, we have $\frac{dA}{dt}=2\pi r\frac{dr}{dt}=2\pi(10)(-\frac{2}{\pi})=-40m^2/s$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Practice Exercises - Page 180: 107
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