Answer
$\frac{1}{2}$
Work Step by Step
$\lim_{\theta\to0}\frac{1-cos\theta}{\theta^2}=\lim_{\theta\to0}\frac{2sin^2(\theta/2)}{4(\theta/2)^2}=\frac{1}{2}\lim_{\theta\to0}(\frac{sin(\theta/2)}{(\theta/2)})^2=\frac{1}{2}(1)^2=\frac{1}{2}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Practice Exercises - Page 180: 102
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